document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=896878>Question 896878</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Alfred, Mindy, and Casey can mow their lawn in 60 minutes if they work together. If it takes Alfred twice as long as Mindy and Casey 10 minutes more than Mindy, how long would it take each to mow the lawn alone? (Round answers to nearest whole minute.)\r<BR>\n" );
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document.write( "I tried organizing the information in a chart and in the time column I have Alfred-2m, Mindy-m, Casey-m+10, and together 60m. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #543829 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=543829\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1/a+1/m+1/c=1/60<BR>\n" );
document.write( "a=2m<BR>\n" );
document.write( "c=m+10<BR>\n" );
document.write( "1/(2m)+1/m+1/(m+10)=1/60\r<BR>\n" );
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document.write( "a=292.315,   c=156.158,   m=146.158<BR>\n" );
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document.write( "a=292,   c=156,   m=146<BR>\n" );
document.write( "check<BR>\n" );
document.write( "60/292+60/156+60/146=950/949<BR>\n" );
document.write( "close enough<BR>\n" );
document.write( "ok<BR>\n" );
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