document.write( "Question 896852: Imagine a sprinter accelerates from rest to maximum speed of 10.8 m/s in 1.8s.in what time interval will he finish. 100 meter race if he keeps the speed constant at 10. 8 m/s for the last part of the race what assumpitions did you make? Please show your work.
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Algebra.Com's Answer #543812 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
the formula for distance under acceleration is:\r
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\n" ); document.write( "\n" ); document.write( "d = v*t + 1/2 * a * t^2\r
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\n" ); document.write( "\n" ); document.write( "d = distance traveled
\n" ); document.write( "v = initial velocity
\n" ); document.write( "t = time
\n" ); document.write( "a = acceleration.\r
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\n" ); document.write( "\n" ); document.write( "you also need the acceleration formula of:\r
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\n" ); document.write( "\n" ); document.write( "a = change in velocity divided by change in time.\r
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\n" ); document.write( "\n" ); document.write( "the runner accelerates from 0 velocity to 10.8 meters per second in 1.8 seconds.\r
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\n" ); document.write( "\n" ); document.write( "the acceleration formula is a = change in velocity divided by time.\r
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\n" ); document.write( "\n" ); document.write( "change in velocity is from 0 to 10.8 meters per second which is equal to 10.8\r
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\n" ); document.write( "\n" ); document.write( "the time is 1.8 seconds.\r
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\n" ); document.write( "\n" ); document.write( "the acceleration is 10.8/1.8 = 6 meters per second squared.\r
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\n" ); document.write( "\n" ); document.write( "now we can find the distance traveled during the acceleration.\r
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\n" ); document.write( "\n" ); document.write( "the formula is d = v*t + 1/2 * a * t^2\r
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\n" ); document.write( "\n" ); document.write( "v*t = 0 because the initial velocity is equal to 0.\r
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\n" ); document.write( "\n" ); document.write( "the formula becomes:\r
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\n" ); document.write( "\n" ); document.write( "d = 0 + 1/2 * a * t^2\r
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\n" ); document.write( "\n" ); document.write( "a is equal to 6 meters per second squared.
\n" ); document.write( "t^2 is equal to 1.8^2.\r
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\n" ); document.write( "\n" ); document.write( "formula becomes:\r
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\n" ); document.write( "\n" ); document.write( "d = 0 + 1/2 * 6 * 1.8^2 which is equal to 9.72 meters.\r
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\n" ); document.write( "\n" ); document.write( "the runner has run 9.72 meters during the runner's acceleration phase.\r
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\n" ); document.write( "\n" ); document.write( "since the race is 110 meters, the runner has another 100.28 meters to go.\r
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\n" ); document.write( "\n" ); document.write( "since rate * time = distance, the formula becomes:\r
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\n" ); document.write( "\n" ); document.write( "10.8 meters per second * time = 100.28 meters.\r
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\n" ); document.write( "\n" ); document.write( "solve for time to get time = 100.28 / 10.8 = 9.29 seconds rounded to the nearest one hundredth of a second.\r
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\n" ); document.write( "\n" ); document.write( "add that to the 1.8 second that the runner took to get up to speed and the total time the runner took to finish the race is is 9.29 + 1.8 = 11.09 seconds.\r
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\n" ); document.write( "\n" ); document.write( "that's your solution if i did this correctly.\r
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\n" ); document.write( "\n" ); document.write( "total time is 11.09 seconds.\r
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