document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=896810>Question 896810</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If f (x) = (x^-x - x^0 + 2^x),  find the following. (Enter your answer as a fraction or mixed number.)<BR>\n" );
document.write( "f (3) =   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #543803 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=543803\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If f (x) = (x^-x - x^0 + 2^x),  find the following. (Enter your answer as a fraction or mixed number.)<BR>\n" );
document.write( "f (3)<BR>\n" );
document.write( "--------------<BR>\n" );
document.write( "Sub 3 for each x<BR>\n" );
document.write( "f(x) = x^-x - x^0 + 2^x<BR>\n" );
document.write( "f(3) = 3^-3 - 3^0 + 2^3<BR>\n" );
document.write( "= 1/27 - 1 + 8<BR>\n" );
document.write( "= 7 + 1/27<BR>\n" );
document.write( "= 190/27 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );