document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=896823>Question 896823</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I can't seem to figure out how to start with this problem...\r<BR>\n" );
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document.write( "The sum of the first two terms of a geometric sequence is 9. The sum to infinity of the corresponding geometric series is 12. Find all possible values of the first term and the common ratio. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #543784 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=543784\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Geometric sequence is defined as<BR>\n" );
document.write( "Xn = ar^(n-1)<BR>\n" );
document.write( "in our case a = 6 and r = 1/2 and the geometric sequence looks like<BR>\n" );
document.write( "6, 3, 3/2, 3/4, .....<BR>\n" );
document.write( "the sum of a geometric sequence to infinity is defined as<BR>\n" );
document.write( "a(1-r^n / 1-r)<BR>\n" );
document.write( "note as n goes to infinity (1/2)^n approaches 0, then we have<BR>\n" );
document.write( "6*(1/ 1/2) = 6*2 = 12<BR>\n" );
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