document.write( "Question 896832: How do I solve for \"x\" in \"-3x^2+2=29\"?
\n" ); document.write( "I know the first thing is to subtract \"29\" from both sides, so:
\n" ); document.write( "\"-3x^2+27=0\"
\n" ); document.write( "From there I am not certain what to do.
\n" ); document.write( "

Algebra.Com's Answer #543777 by Alan3354(69443)\"\" \"About 
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How do I solve for \"x\" in \"-3x^2+2=29\"?
\n" ); document.write( "I know the first thing is to subtract \"29\" from both sides, so:
\n" ); document.write( "\"-3x^2+27=0\"
\n" ); document.write( "-------------
\n" ); document.write( "-3x^2+2=29
\n" ); document.write( "Or, subtract 2
\n" ); document.write( "-3x^2 = 27
\n" ); document.write( "Divide by -3
\n" ); document.write( "x^2 = -9
\n" ); document.write( "---
\n" ); document.write( "\"x+=+%2B3i\"
\n" ); document.write( "\"x+=+-3i\"
\n" ); document.write( "\"i+=+sqrt%28-1%29\"
\n" ); document.write( "
\n" ); document.write( "
\n" );