document.write( "Question 896832: How do I solve for \"x\" in \"-3x^2+2=29\"?
\n" ); document.write( "I know the first thing is to subtract \"29\" from both sides, so:
\n" ); document.write( "\"-3x^2+27=0\"
\n" ); document.write( "From there I am not certain what to do.
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Algebra.Com's Answer #543776 by josgarithmetic(39625)\"\" \"About 
You can put this solution on YOUR website!
\"-3x%5E2=29-2\"
\n" ); document.write( "\"-3x%5E2=27\"
\n" ); document.write( "\"x%5E2=%2827%29%2F%28-3%29\"
\n" ); document.write( "\"x%5E2=-9\"
\n" ); document.write( "\"sqrt%28x%5E2%29=0%2B-+sqrt%28-9%29\"
\n" ); document.write( "\"highlight%28x=0%2B-+3i%29\"\r
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\n" ); document.write( "\n" ); document.write( "-\r
\n" ); document.write( "\n" ); document.write( "The 0 in the answer is only included for rendering on the page and is not really needed.\r
\n" ); document.write( "\n" ); document.write( "-
\n" ); document.write( "\"i%5E2=-1\" means that \"i=-sqrt%28-1%29\" or \"i=sqrt%28-1%29\".
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