document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=896791>Question 896791</A>: <I><SPAN STYLE=\"word-break: break-all;\"> You are standing on a ladder, helping with some repairs at home. You drop a hammer and it hits the floor at a speed if 8 feet per second. If the acceleration due to gravity(g) is 32 feet/second^2,how far above the ground(h) was the hammer when you dropped it? use the formula v = &#8730;2gh Any help would be appreciated :-) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #543752 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=543752\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> velocity(v) = square root(2gh)<BR>\n" );
document.write( "8 = square root(2*32*h)<BR>\n" );
document.write( "square both sides of =<BR>\n" );
document.write( "64 = 64*h<BR>\n" );
document.write( "h = 1 foot<BR>\n" );
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