document.write( "Question 896742: what is 9t^2 +12t + 4 factored completely ?\r
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Algebra.Com's Answer #543724 by harpazo(655)![]() ![]() You can put this solution on YOUR website! what is 9t^2 +12t + 4 factored completely ?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "I will use the Grouping Method.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "9 x 4 = 36\r \n" ); document.write( "\n" ); document.write( "Ask yourself: What two numbers when multiplied together yield 36 but when added will produce a sum of 12?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "What about 6 x 6?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Yes, we found our two factors.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We now form a large polynomial.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "9t^2 + 6t + 6t + 4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Are you following me so far?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We now make our two groups.\r \n" ); document.write( "\n" ); document.write( "Group 1 is 9t^2 + 6t.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We factor this first group.\r \n" ); document.write( "\n" ); document.write( "3t(3t + 2).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Our second group is 6t + 4.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2(3t + 2).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Answer: (3t + 2)(3t + 2) \n" ); document.write( " |