document.write( "Question 896731: the sum of the ages of the girl and brother is 26 years. 3 years ago her age was four time the age of her brother. find the present ages of the girl and brother?? \n" ); document.write( "
Algebra.Com's Answer #543719 by YvonneGodsway(2)![]() ![]() You can put this solution on YOUR website! Let girl be x and boy be y. \n" ); document.write( "x+y=26 \n" ); document.write( "x=26-y \n" ); document.write( "3 years ago; \n" ); document.write( "boy was y-3 \n" ); document.write( "girl was x-3 \n" ); document.write( "since girl was 4 times age of girl, \n" ); document.write( "x-3=4(y-3) \n" ); document.write( "x-3=4y-12 \n" ); document.write( "since x=26-y \n" ); document.write( "(26-y)-3=4y-12 \n" ); document.write( "23-y=4y-12 \n" ); document.write( "23+12=4y+y \n" ); document.write( "35=5y \n" ); document.write( "y=7 \n" ); document.write( "x=26-7 \n" ); document.write( "x=19 \n" ); document.write( "hence girl is 19years and boy is 7years \n" ); document.write( " \n" ); document.write( " |