document.write( "Question 896731: the sum of the ages of the girl and brother is 26 years. 3 years ago her age was four time the age of her brother. find the present ages of the girl and brother?? \n" ); document.write( "
Algebra.Com's Answer #543719 by YvonneGodsway(2)\"\" \"About 
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Let girl be x and boy be y.
\n" ); document.write( "x+y=26
\n" ); document.write( "x=26-y
\n" ); document.write( "3 years ago;
\n" ); document.write( "boy was y-3
\n" ); document.write( "girl was x-3
\n" ); document.write( "since girl was 4 times age of girl,
\n" ); document.write( "x-3=4(y-3)
\n" ); document.write( "x-3=4y-12
\n" ); document.write( "since x=26-y
\n" ); document.write( "(26-y)-3=4y-12
\n" ); document.write( "23-y=4y-12
\n" ); document.write( "23+12=4y+y
\n" ); document.write( "35=5y
\n" ); document.write( "y=7
\n" ); document.write( "x=26-7
\n" ); document.write( "x=19
\n" ); document.write( "hence girl is 19years and boy is 7years
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