document.write( "Question 75699: can some help me simplify this?\r
\n" ); document.write( "\n" ); document.write( "x^2+2x-80
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Algebra.Com's Answer #54369 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Simplify:
\n" ); document.write( "\"x%5E2%2B2x-80\" This trinomial can be factored.
\n" ); document.write( "The factors will take the form: (x+m)(x+n) where m and n must meet the follwing restrictions:
\n" ); document.write( "m*n = -80 and
\n" ); document.write( "m+n = 2
\n" ); document.write( "How do we know this?
\n" ); document.write( "Well, when you multiply the two factors, you should get back the original trinomial, right? Right!...so, usinf FOIL:
\n" ); document.write( "\"%28x%2Bm%29%28x%2Bn%29+=+x%5E2%2Bnx%2Bmx%2Bnm\" = \"x%5E2%2B%28m%2Bn%29x%2Bm%2An\" and if you compare this with the original trinomial, you can see that:
\n" ); document.write( "m+n = 2 and
\n" ); document.write( "m*n = -80
\n" ); document.write( "Since the sum of m and n is quite small (2), this would indicate that the absolute values of m and n are are very close to each other.
\n" ); document.write( "A wise choice would be:
\n" ); document.write( "m = 10 and n = -8 or
\n" ); document.write( "m = -10 and n = 8
\n" ); document.write( "because both of their products are -80.
\n" ); document.write( "Select the pair whose sum is 2, that has to be m = 10 and n = -8.
\n" ); document.write( "So, now you can write:
\n" ); document.write( "\"x%5E2%2B2x-80+=+%28x%2B10%29%28x-8%29\"
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