document.write( "Question 896643: The length of a rectangle is
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\n" ); document.write( " longer than its width.
\n" ); document.write( "If the perimeter of the rectangle is
\n" ); document.write( "46
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\n" ); document.write( " , find its area.
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Algebra.Com's Answer #543679 by MathTherapy(10552)\"\" \"About 
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\n" ); document.write( "The length of a rectangle is 5 cm longer than its width. If the perimeter of the rectangle is 46 cm, find its area.
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\n" ); document.write( "Let width be W
\n" ); document.write( "Then length = W + 5
\n" ); document.write( "Since perimeter = 46, then: 2W + 2(W + 5) = 46
\n" ); document.write( "2W + 2W + 10 = 46
\n" ); document.write( "4W + 10 = 46
\n" ); document.write( "4W = 46 – 10
\n" ); document.write( "4W = 36
\n" ); document.write( "W, or width = \"36%2F4\", or 9
\n" ); document.write( "Length: 9 + 5, or 14
\n" ); document.write( "Area: 9(14), or \"highlight_green%28126%29\" sq cm \n" ); document.write( "
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