document.write( "Question 896643: The length of a rectangle is
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\n" ); document.write( "If the perimeter of the rectangle is
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Algebra.Com's Answer #543677 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
Easiest to find the length and width first, and then use them for area.\r
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\n" ); document.write( "\n" ); document.write( "w for width, L for length, p for perimeter.
\n" ); document.write( "Assume p is known, k is known, and w and L unknowns.
\n" ); document.write( "\"L=w%2Bk\" and \"p=2w%2B2L\".
\n" ); document.write( "k=5 and p=46;
\n" ); document.write( "but staying completely in symbols, you first want to solve for w and L.\r
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\n" ); document.write( "\n" ); document.write( "\"2w%2B2L=p\"
\n" ); document.write( "\"2w%2B2%28w%2Bk%29=p\"
\n" ); document.write( "\"2w%2B2w%2B2k=p\"
\n" ); document.write( "\"4w%2B2k=p\"
\n" ); document.write( "\"4w=p-2k\"
\n" ); document.write( "\"highlight%28w=%28p-2k%29%2F4%29\".
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\n" ); document.write( "\"L=w%2Bk\"
\n" ); document.write( "\"L=%28p-2k%29%2F4%2Bk\"
\n" ); document.write( "\"L=%28p-2k%29%2F4%2B4k%2F4\"
\n" ); document.write( "\"L=%28%28p-2k%29%2B4k%29%2F4\"
\n" ); document.write( "\"L=%28p-2k%2B4k%29%2F4\"
\n" ); document.write( "\"highlight%28L=%28p%2B2k%29%2F4%29\"
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\n" ); document.write( "Spend some time checking how those formulas look for w and L. See how they resemble each other but are not the same.\r
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\n" ); document.write( "\n" ); document.write( "Remember, the question was, FIND AREA.\r
\n" ); document.write( "\n" ); document.write( "This means find \"highlight_green%28w%2AL%29\".\r
\n" ); document.write( "\n" ); document.write( "Using the formulas for L and w,
\n" ); document.write( "\"wL=%28%28p-2k%29%2F4%29%2A%28%28p%2B2k%29%2F4%29\"
\n" ); document.write( "\"%28p%5E2-%282k%29%5E2%29%2F16\"
\n" ); document.write( "\"highlight%28%28p%5E2-4k%5E2%29%2F16%29\"-----The AREA, in symbolic form.
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\n" ); document.write( "Now, just substitute the given values from the description to find value for the area.
\n" ); document.write( "\"%2846%5E2-4%2A5%5E2%29%2F16\"
\n" ); document.write( "\"2016%2F16\"
\n" ); document.write( "\"highlight%28126%29\", square centimeters
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