document.write( "Question 896598: In a rectangle with perimeter 30 cm and area 56 cm, the longer sides length is one cm more than the shorter side. \n" ); document.write( "

Algebra.Com's Answer #543651 by josgarithmetic(39617) $\"\"$ $\"About$

You can put this solution on YOUR website!
y=x+1 for sides x and y.\r
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\n" ); document.write( "\n" ); document.write( " $\"2x%2B2y=30\"$
\n" ); document.write( " $\"x%2By=15\"$
\n" ); document.write( " $\"x%2Bx%2B1=15\"$
\n" ); document.write( " $\"2x=14\"$
\n" ); document.write( " $\"highlight%28x=7%29\"$
\n" ); document.write( "AND
\n" ); document.write( " $\"x%28x%2B1%29=56\"$ but we already found x; so this equation simply tells us what we already could find without being given this area.\r
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\n" ); document.write( "\n" ); document.write( "Move on to find y.
\n" ); document.write( " $\"highlight%28y=8%29\"$ .\r
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\n" ); document.write( "\n" ); document.write( "You could have ignored the perimeter information and just used the area information along with the sides relationship to find the dimensions. \n" ); document.write( "

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