document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=896604>Question 896604</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a train leaves the station at 1 pm It travels an average rate of 60 mi/hr A high speed train leaves the same station an hour later traveling at an average rate of 96 mi/hr The second train follows the same route as the first train on a parallel track In how many hours will the second train catch up with the first train </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #543644 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=543644\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The first train traveled 60 miles in that hour<BR>\n" );
document.write( "The second train needs to make up that 60 miles<BR>\n" );
document.write( "It is gaining on the first train at 36 mph.<BR>\n" );
document.write( "Tt will take it 60/36=10/6=5/3 =1 2/3 hours or 1 hour and 40 minutes to catch up.<BR>\n" );
document.write( "Another way<BR>\n" );
document.write( "60(x+1)=96x<BR>\n" );
document.write( "60x+60=96x<BR>\n" );
document.write( "60=36x<BR>\n" );
document.write( "5=3x<BR>\n" );
document.write( "5/3=x\r<BR>\n" );
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document.write( " </SPAN>\n" );
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