document.write( "Question 75680This question is from textbook Algebra 1
\n" ); document.write( ": 1.) k+1/2 < k/4+2 When solved the inequality k was = to 0, so the variable was 0! \n" ); document.write( "
Algebra.Com's Answer #54362 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"k%2B1%2F2+%3C+k%2F4%2B2\"
\n" ); document.write( "\"4%28k%2B1%2Fcross%282%29%29+%3C+cross%284%29%28k%2Fcross%284%29%2B2%29\" Multiply both sides by 4 (this is the LCD). This clears any denominators
\n" ); document.write( "\"4k%2B2%3Ck%2B8\"
\n" ); document.write( "\"3k%2B2%3C8\" Subtract k from both sides
\n" ); document.write( "\"3k%3C6\" Subtract 2 from both sides
\n" ); document.write( "\"k%3C2\" Divide both sides by 3. This is your solution set
\n" ); document.write( "If you want the answer in interval notation it is:
\n" ); document.write( "
\n" ); document.write( "I'm not sure where you got an answer of 0 from, so double check your steps or tell me if I translated something wrong.
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\n" ); document.write( "Check:
\n" ); document.write( "To test our solution set, pick any number that is less than 2 and plug it into k
\n" ); document.write( "\"1%2B1%2F2+%3C+1%2F4%2B2\" Let k=1
\n" ); document.write( "\"2%2F2%2B1%2F2+%3C+1%2F4%2B8%2F4\"
\n" ); document.write( "\"3%2F2+%3C+9%2F4\"
\n" ); document.write( "\"3%2F2+%3C+9%2F4\"
\n" ); document.write( "\"1.5%3C2.25\" works. \n" ); document.write( "

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