document.write( "Question 896539: how much of a 25% acid solution must be mixed with 4 gallons of an 18% acid solution to get a 21% acid solution? \n" ); document.write( "
Algebra.Com's Answer #543586 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! how much of a 25% acid solution must be mixed with 4 gallons of an 18% acid solution to get a 21% acid solution? \n" ); document.write( "----------------- \n" ); document.write( "Equation: \n" ); document.write( "acid + acid = acid \n" ); document.write( "---- \n" ); document.write( "0.25x + 0.18*4 = 0.21(x+4) \n" ); document.write( "------ \n" ); document.write( "25x + 18*4 = 21x + 21*4 \n" ); document.write( "------- \n" ); document.write( "4x = 3*4 \n" ); document.write( "x = 3 gallongs (amt. of 25% solution needed) \n" ); document.write( "-------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "-------------- \n" ); document.write( " |