document.write( "Question 896539: how much of a 25% acid solution must be mixed with 4 gallons of an 18% acid solution to get a 21% acid solution? \n" ); document.write( "
Algebra.Com's Answer #543586 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
how much of a 25% acid solution must be mixed with 4 gallons of an 18% acid solution to get a 21% acid solution?
\n" ); document.write( "-----------------
\n" ); document.write( "Equation:
\n" ); document.write( "acid + acid = acid
\n" ); document.write( "----
\n" ); document.write( "0.25x + 0.18*4 = 0.21(x+4)
\n" ); document.write( "------
\n" ); document.write( "25x + 18*4 = 21x + 21*4
\n" ); document.write( "-------
\n" ); document.write( "4x = 3*4
\n" ); document.write( "x = 3 gallongs (amt. of 25% solution needed)
\n" ); document.write( "--------------
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "--------------
\n" ); document.write( "
\n" );