document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=896465>Question 896465</A>: <I><SPAN STYLE=\"word-break: break-all;\"> five numbers are represented by a b c d and e. the average of a, b, and c is 8. the average of a b c d and e is 7.2. Given that e is twice d, find the value of e </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #543584 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=543584\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a + b + c = 24 (8 * 3)<BR>\n" );
document.write( "a + b + c + d + e = 36 (5 * 7.2)<BR>\n" );
document.write( "Therefore, d + e = 12 (36-24)<BR>\n" );
document.write( "E = 2D<BR>\n" );
document.write( "D + e = 12<BR>\n" );
document.write( "d + 2D = 12<BR>\n" );
document.write( "3D = 12<BR>\n" );
document.write( "D = 4<BR>\n" );
document.write( "If D is 4, then E is 8 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );