document.write( "Question 896477: A rope of lenght 2m is divided into three pieces whose lengths are in a geometric sequence. The longest piece is twice as long as the shortest piece. find the common ratio of the sequence and the exact length of the shortest piece of rope ( without a GCD). \n" ); document.write( "
Algebra.Com's Answer #543533 by Theo(13342) You can put this solution on YOUR website! the nth term of a geometric series is given by the formula of:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "An = A1 * r^(n-1)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the sum of this geometric series must be equal to 2 because that's the overall length of your rope.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your problem states that the longest piece is 2 times the length of the shortest piece.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this means that, if the shortest piece is equal to x, then the longest piece must be equal to 2x.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your rope is being divided into 3 segments, so the value of n in your series will be equal to 3.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your sequence becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "A1 = x \n" ); document.write( "A2 = x*r \n" ); document.write( "A3 = x*r^2 = 2x *****\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "***** A3 is equal to 2x and 2x is equal to x*r^2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your equation to solve from A3 is 2x = x^r^2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "divide both sides of this equation by x to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2x/x = r^2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "solve for r^2 to get r^2 = 2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "solve for r to get r = sqrt(2)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your common ratio is sqrt(2)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your geometric series becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "A1 = x \n" ); document.write( "A2 = x*sqrt(2) \n" ); document.write( "A3 = x*sqrt(2)^2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the formula for the sum of a geometric series is:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Sn = A1 * (1 - r^n) / (1-r)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you know that Sn = 2 because that's the length of your rope.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you know that r = sqrt(2) because you just solved for that.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you know that A1 = x because that's the letter you assigned to represent the value of A1.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the Sn formula becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2 = x * (1 - sqrt(2)^3) / (1 - sqrt(2))\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "multiply both sides of this formula by (1 - sqrt(2)) to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2 * (1 - sqrt(2)) = x * (1 - sqrt(2)^3)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "divide both sides of this formula by (1 - sqrt(2)^3) to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2 * (1 - sqrt(2)) / (1 - sqrt(2)^3) = x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that's the value of x which is the value of A1 which is the smallest length of rope.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "r = sqrt(2)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "A1 = 2 * (1 - sqrt(2)) / (1 - sqrt(2)^3)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "i'll use my calculator to confirm for you that the sum of the geometric series for n = 1 to 3 is equal to 2 which is the length of the rope, and that the smallest length of the rope is equal to A1 as shown above.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "using my calculator, and using the formula of An = A1 * r^(n-1) for n = 1 to 3, i get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "A1 = .4530818393 \n" ); document.write( "A2 = .640754482 \n" ); document.write( "A3 = .9061636786\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "sum(A1 to A3) = 2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "use your calculator to solve for A1 and you will see that:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "A1 = 2 * (1 - sqrt(2)) / (1 - sqrt(2)^3) = .4530818393\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your solutions are:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "r = sqrt(2)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "A1 = 2 * (1 - sqrt(2)) / (1 - sqrt(2)^3)\r \n" ); document.write( "\n" ); 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