document.write( "Question 896368: Coin question
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document.write( "Natalie has some nickels, Dirk has some dimes and Quincy has some quarters. Dirk has five more dimes than Quincy has quarters. If Natalie gives Dirk a nickel, Dirk gives Quincy a dime, and Quincy gives Natalie a quarter; they will all have the same amount of money. How many coins did each have originally?
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document.write( "I set up an equation to show how much money Dirk has: .10d + .05 - .10 where d is the number of dimes. For Quincy: .25q + .10 - .25 where q is the number of quarters. I also set up 5 + d = q to show that Dirk has 5 more coins than Quincy then I solved for d (d = q - 5) and substituted that in Dirks formula, but this isn't working. I know intuitively that they each end up with $.85 and that means Natalie has 13 coins, Dirk has 9 and Quincy has 4 at the beginning, but I can't figure out how to write this as an equation. I appreciate the help, Judy \n" );
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Algebra.Com's Answer #543456 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Natalie has some nickels, Dirk has some dimes and Quincy has some quarters. \n" ); document.write( " Dirk has five more dimes than Quincy has quarters. \n" ); document.write( "d = q + 5 \n" ); document.write( "If Natalie gives Dirk a nickel, Dirk gives Quincy a dime, and Quincy gives Natalie a quarter; they will all have the same amount of money. \n" ); document.write( ".10d + .05 - .10 = .25q +.10 - .25 \n" ); document.write( ".10d -.05 = .25q - .15 \n" ); document.write( ".10d = .25q -.15 + .05 \n" ); document.write( ".10d = .25q - .10 \n" ); document.write( "multiply by 10 \n" ); document.write( "d = 2.5q - 1 \n" ); document.write( "we know that d = q + 5 \n" ); document.write( "q + 5 = 2.5q - 1 \n" ); document.write( "5 + 1 = 2.5q - q \n" ); document.write( "6 = 1.5q \n" ); document.write( "q = 6/1.5 \n" ); document.write( "q = 4 quarters \n" ); document.write( "then \n" ); document.write( "d = 4 + 5 = 9 dimes \n" ); document.write( ": \n" ); document.write( "Find n: \n" ); document.write( ".05n -.05 + .25 = .05n + .20 \n" ); document.write( "we know that \n" ); document.write( ".05n + .20 = .25q -.15 \n" ); document.write( "Replace q with 4 \n" ); document.write( ".05n + .20 = 1.0 - .15 \n" ); document.write( ".05n = .85 - .20 \n" ); document.write( ".05n = .65 \n" ); document.write( "n = .65/.05 \n" ); document.write( "n = 13 nickels \r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " How many coins did each have originally? \n" ); document.write( " |