document.write( "Question 896344: Please find the domain of the following function:
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document.write( " sqrt(2x^3-x^2-18x+9) \n" );
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Algebra.Com's Answer #543429 by Theo(13342)![]() ![]() You can put this solution on YOUR website! you want to find out the intervals where the square root is positive. \n" ); document.write( "those intervals will be your domain.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "start with 2x^3 - x^2 - 18x + 9 = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "fortunately this factors cleanly.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "if not, then you probably would need to graph the equation to see where the intervals lie.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "graphing is the easiest way if you have a graphing calculator handy.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "i did both.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "first the factoring method.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your equation to factor is:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2x^3 - x^2 - 18x + 9 = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "break this up into 2 separate parts as shown below:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(2x^3 - x^2) - (18x - 9) = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "factor the first part to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x^2 * (2x - 1) - (18x - 9) = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "factor the second part so the expression in the parentheses will be equal to 2x - 1.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x^2 * (2x - 1) - 9 * (2x - 1) = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "factor out the common term of (2x - 1) to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(x^2 - 9) * (2x - 1) = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x^2 - 9 can further be factored into (x - 3) * (x + 3)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your equation becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(x - 3) * (x + 3) * (2x - 1) = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the roots of this equation are:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = 3 \n" ); document.write( "x = -3 \n" ); document.write( "x = 1/2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "those are the values of x where the value of the equation is equal to 0.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "in other words, the graph of the equations crosses the x-axis at those values of x.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you now need to test each interval to see whether the graph is negative or positive in those intervals.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "first interval is x < -3 \n" ); document.write( "graph is negative there.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "second interval is x > -3 and < 1/2 \n" ); document.write( "graph is positive there.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "third interval is x > 1/2 and < 3 \n" ); document.write( "graph is negative there.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "fourth interval is x > 3 \n" ); document.write( "graph is positive there.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your domain is the intervals where the square root of the equation is not negative.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "those intervals will be:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-3 <= x <= 1/2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x >= 3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "here's a graph of the equation within the square root sign where you wanted to find the intervals where it was positive and where it was negative.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the equation used is y = 2x^3 - x^2 - 18x + 9\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "here's a graph of the equation you wanted to find the domain for.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that equation is y = sqrt(2x^3 - x^2 - 18x + 9)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "since the intervals where the square root is negative are invalid because they don't result in any real values, the graph is missing in those intervals.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |