document.write( "Question 896320: Mr jacob is 55 years old and tony is 7 years old. in how many yearswill mr jacob be 4 times as old as tony \n" ); document.write( "
Algebra.Com's Answer #543404 by thesvw(77)![]() ![]() You can put this solution on YOUR website! Let Jacobs age be 'J' years when Tony's age is as 4 times as Jacobs. Let Tony's age be 'T'.\r \n" ); document.write( "\n" ); document.write( "J = 4T\r \n" ); document.write( "\n" ); document.write( "The difference between Jacobs and Tonys ages doesn't change. (55 -7= 48)\r \n" ); document.write( "\n" ); document.write( "J - T = 48\r \n" ); document.write( "\n" ); document.write( "J = 48 + T\r \n" ); document.write( "\n" ); document.write( "J = 4T\r \n" ); document.write( "\n" ); document.write( "48 + T = 4T\r \n" ); document.write( "\n" ); document.write( "48 = 3T\r \n" ); document.write( "\n" ); document.write( "48/3 = T\r \n" ); document.write( "\n" ); document.write( "T = 16\r \n" ); document.write( "\n" ); document.write( "Now Tony is 7. In 9 years.. It will happen. \n" ); document.write( " |