document.write( "Question 896291: 4 taps together fill 5 drums in 5 hours. How many drums can be filed by 10 taps in 6 hours ?
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Algebra.Com's Answer #543374 by Theo(13342) You can put this solution on YOUR website! rate per tap * number of taps * time = quantity of work produced.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "let R = rate per tap \n" ); document.write( "let N = number of taps \n" ); document.write( "let T = time \n" ); document.write( "let Q = quantity of work produced\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the formula becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "R*N*T = Q\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "replace N with 4 and T with 5 and Q with 5 and you get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "R*4*5 = 5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "solve for R to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "R = 5/(4*5) = 1/4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "each tap can fill 1/4 of a drum in one hour.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "4 taps can therefore fill 1 drum in one hour.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "4 taps can therefore fill 5 drums in 5 hours.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the formula looks good and the rate per tap is equal to 1/4 of a drum per hour.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "now you want to know how many drums can be filled by 10 taps in 6 hours.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the same formula applies:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "R*N*T = Q\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "R = 1/4 \n" ); document.write( "N = 10 \n" ); document.write( "T = 6 \n" ); document.write( "Q will be equal to 1/4 * 10 * 6 = 15 drums.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that's your solution.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "15 drums can be filled by 10 taps in 6 hours.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "each tap can fill 1/4 of a drum per hour.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that means that 10 taps can fill 10/4 drums per hour.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "multiply 10/4 by 6 and you get 60/4 which is equal to 15 drums in 6 hours.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |