document.write( "Question 75645: 5) The first side of a triangle is 5 inches less than the second side, and the third side is twice as long as the first sides. If the perimeter of the triangle is 33 iches, find the lengths of the sides of the triangle.\r
\n" ); document.write( "\n" ); document.write( "6) The shortest side of a triangle is 8 feet less than the medium side, and the longest side is 4 feetlonger than 3 times the shortest side. If the perimeter is 27 feet, find the length of the shortest side.
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Algebra.Com's Answer #54335 by checkley75(3666)\"\" \"About 
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LET X BE THE SECOND SIDE
\n" ); document.write( "X-5 IS THE FIRST SIDE
\n" ); document.write( "2(X-5) IS THE THIRD SIDE
\n" ); document.write( "NOW WE ADD ALL THREE SIDES & SET THEM EQUAL TO 33
\n" ); document.write( "X+(X-5)+2(X-5)=33
\n" ); document.write( "4X-5-10=33
\n" ); document.write( "4X=33+15
\n" ); document.write( "4X=48
\n" ); document.write( "X=48/4
\n" ); document.write( "X=12 INCHES FOR THE FIRST SIDE
\n" ); document.write( "12-5=7 FOR THE SECOND SIDE &
\n" ); document.write( "2(12-5)=2*7=14 FOR THE THIRD SIDE
\n" ); document.write( "PROOF
\n" ); document.write( "12+7+14=33
\n" ); document.write( "33=33
\n" ); document.write( "-------------------------------------------------------
\n" ); document.write( "LET M=MEDIUM SIDE
\n" ); document.write( "M-8=SHORTEST SIDE
\n" ); document.write( "3(M-8)+4=LONGEST SIDE
\n" ); document.write( "M+(M-8)+3(M-8)+4=27
\n" ); document.write( "M+M-8+3M-24+4=27
\n" ); document.write( "5M=27+8+24-4
\n" ); document.write( "5M=55
\n" ); document.write( "M=55/5
\n" ); document.write( "M=11 THE MEDIUM SIDE
\n" ); document.write( "THE SHORTEST SIDE IS 11-8=3 FEET.
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