document.write( "Question 896221: Latifah opens a bank account with $800. The account accrues 6% interest compounded annually.\r
\n" ); document.write( "\n" ); document.write( "How much money will she have in her account at the end of 2 years, rounded to the nearest cent?
\n" ); document.write( "

Algebra.Com's Answer #543331 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
We'll be using the formula \"A+=+P%2A%281%2Br%2Fn%29%5E%28n%2At%29\" where\r
\n" ); document.write( "\n" ); document.write( "A = amount in the account after t years
\n" ); document.write( "P = initial deposit (principal)
\n" ); document.write( "r = interest rate as a decimal
\n" ); document.write( "n = compounding frequency
\n" ); document.write( "t = number of years\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "In this case,\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "A = unknown (we're solving for it)
\n" ); document.write( "P = 800
\n" ); document.write( "r = 0.06 (6% = 6/100 = 0.06)
\n" ); document.write( "n = 1 (compounded annually = compounding 1 time per year)
\n" ); document.write( "t = 2 years\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Plug all this info into the formula to get...\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"A+=+P%2A%281%2Br%2Fn%29%5E%28n%2At%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"A+=+800%2A%281%2B0.06%2F1%29%5E%281%2A2%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"A+=+800%2A%281%2B0.06%29%5E%281%2A2%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"A+=+800%2A%281.06%29%5E%281%2A2%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"A+=+800%2A%281.06%29%5E%282%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"A+=+800%2A%281.1236%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"A+=+898.88\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "She will have $898.88 in the account at the end of the two years.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Side Note: She has earned A - P = 898.88 - 800 = $98.88 in interest alone.
\n" ); document.write( "
\n" );