document.write( "Question 896187: How would f^-1 look on a graph? \n" ); document.write( "
Algebra.Com's Answer #543302 by Edwin McCravy(20055)\"\" \"About 
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document.write( "Here's an example of what it looks like:\r\n" );
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document.write( "Suppose the graph of \"y=%22f%28x%29%22\" looks like this:\r\n" );
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document.write( "Then to draw its inverse we would begin by drawing the identity line\r\n" );
document.write( "which is where y and x are identical, that is the line y = x, a line \r\n" );
document.write( "through the origin that rises at a 45° angle.  We'll draw it dotted,\r\n" );
document.write( "in green:\r\n" );
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document.write( "Now we'll reflect that graph across the green identity line y = x, and get\r\n" );
document.write( "this blue graph, y = f-1(x)\r\n" );
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document.write( "That's an example of what the graph of the inverse of a function y = f-1(x) looks \r\n" );
document.write( "like.  It's the reflection of the graph of y = f(x) across the identity line,\r\n" );
document.write( "whose equation is y = x.\r\n" );
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document.write( "Notice that the red graph contains the point (1,-5) and the blue inverse\r\n" );
document.write( "graph contains the point (-5,1).  All points are like that. If a point \r\n" );
document.write( "(a,b) in on the red graph, then the reversed point (b,a) will be on the blue\r\n" );
document.write( "inverse graph, and vice-versa.\r\n" );
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document.write( "Edwin
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