document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=896194>Question 896194</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A number with three digits has the hundred digit 3 times the unit digit. The sum of the digits is 19. If the digits are written in reversed order, the value of the number is decreased by 594. Find the number.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #543295 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=543295\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 100a+10b+c=x,<BR>\n" );
document.write( "100c+10b+a=y,<BR>\n" );
document.write( "x-y=594,<BR>\n" );
document.write( "a=3c,<BR>\n" );
document.write( "a+b+c=19\r<BR>\n" );
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document.write( "973 becomes 379<BR>\n" );
document.write( "973-379=594\r<BR>\n" );
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document.write( "BTW <BR>\n" );
document.write( "There are only three possibilities for a=3c but two of the sums don't work<BR>\n" );
document.write( "1+3+15 doesn't work<BR>\n" );
document.write( "2+6+11 doesn't work<BR>\n" );
document.write( "3+9+7=19 works<BR>\n" );
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