document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=896093>Question 896093</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is three times its width. If the<BR>\n" );
document.write( "length is decreased by 20 ft. and the width increased by 10 ft.,<BR>\n" );
document.write( "the area is increased by 200 sq. ft. Fund the dimensions<BR>\n" );
document.write( "of the rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #543250 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=543250\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> length(l) = 3*width(w) and<BR>\n" );
document.write( "Area = 3w^2<BR>\n" );
document.write( "(3w-20) * (w+10) = 3w^2 + 200<BR>\n" );
document.write( "3w^2 +10w -200 = 3w^2 +200<BR>\n" );
document.write( "10w = 400<BR>\n" );
document.write( "w = 40 feet<BR>\n" );
document.write( "l = 120 feet<BR>\n" );
document.write( "check answer<BR>\n" );
document.write( "100 * 50 = 4800 + 200<BR>\n" );
document.write( "5000 = 5000<BR>\n" );
document.write( "our answer checks\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );