document.write( "Question 895997: Write the standard form equation of the conic section.
\n" ); document.write( "Eccentricity = 3/5
\n" ); document.write( "Foci: (6,1), (6,-11)\r
\n" ); document.write( "\n" ); document.write( "The answer is (x-6)^2 / 64 + (y+5)^2 /100 = 1
\n" ); document.write( "I don't understand how to do this problem.
\n" ); document.write( "Thank you.
\n" ); document.write( "

Algebra.Com's Answer #543221 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
Write the standard form equation of the conic section.
\n" ); document.write( "Eccentricity = 3/5
\n" ); document.write( "Foci: (6,1), (6,-11)
\n" ); document.write( "The answer is (x-6)^2 / 64 + (y+5)^2 /100 = 1
\n" ); document.write( "***
\n" ); document.write( "Conic section is an ellipse with vertical major axis.(from given foci coordinates)
\n" ); document.write( "Its standard form of equation:\"%28x-h%29%5E2%2Fb%5E2%2B%28y-k%29%5E2%2Fa%5E2=1\", a>b, (h,k)=coordinates of center
\n" ); document.write( "..
\n" ); document.write( "x-coordinate of center=6 (from foci data)
\n" ); document.write( "y-coordinate of center=-5 (midpoint between 1 and -11)
\n" ); document.write( "center: (6,-5)
\n" ); document.write( "c=6(distance from center to foci)
\n" ); document.write( "c^2=36
\n" ); document.write( "eccentricity=3/5=c/a
\n" ); document.write( "3a=5c
\n" ); document.write( "a=5c/3=30/3=10
\n" ); document.write( "a^2=100
\n" ); document.write( "c^2=a^2-b^2
\n" ); document.write( "b^2=a^2-c^2=100-36=64
\n" ); document.write( "equation:\"%28x-6%29%5E2%2F64%2B%28y%2B5%29%5E2%2F100=1\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );