document.write( "Question 895997: Write the standard form equation of the conic section.
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document.write( "Eccentricity = 3/5
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document.write( "Foci: (6,1), (6,-11)\r
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document.write( "The answer is (x-6)^2 / 64 + (y+5)^2 /100 = 1
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document.write( "I don't understand how to do this problem.
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document.write( "Thank you. \n" );
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Algebra.Com's Answer #543221 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Write the standard form equation of the conic section. \n" ); document.write( "Eccentricity = 3/5 \n" ); document.write( "Foci: (6,1), (6,-11) \n" ); document.write( "The answer is (x-6)^2 / 64 + (y+5)^2 /100 = 1 \n" ); document.write( "*** \n" ); document.write( "Conic section is an ellipse with vertical major axis.(from given foci coordinates) \n" ); document.write( "Its standard form of equation: \n" ); document.write( ".. \n" ); document.write( "x-coordinate of center=6 (from foci data) \n" ); document.write( "y-coordinate of center=-5 (midpoint between 1 and -11) \n" ); document.write( "center: (6,-5) \n" ); document.write( "c=6(distance from center to foci) \n" ); document.write( "c^2=36 \n" ); document.write( "eccentricity=3/5=c/a \n" ); document.write( "3a=5c \n" ); document.write( "a=5c/3=30/3=10 \n" ); document.write( "a^2=100 \n" ); document.write( "c^2=a^2-b^2 \n" ); document.write( "b^2=a^2-c^2=100-36=64 \n" ); document.write( "equation: \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |