document.write( "Question 896065: A rectangle is twice as long as it is wide. The perimeter is 60 feet. Find the dimensions. \n" ); document.write( "
Algebra.Com's Answer #543204 by JulietG(1812)![]() ![]() You can put this solution on YOUR website! P = 2L + 2W \n" ); document.write( "P = 60 \n" ); document.write( "L = 2W \n" ); document.write( "Insert the known values. \n" ); document.write( "P = 2L + 2W \n" ); document.write( "60 = 2(2W) + 2W \n" ); document.write( "Distribute \n" ); document.write( "60 = 4W + 2W \n" ); document.write( "60 = 6W \n" ); document.write( "Divide each side by 6 \n" ); document.write( "W = 10 \n" ); document.write( "If the width is 10 and the length is twice that, it's 20. \n" ); document.write( "20+20+10+10 = 60 \n" ); document.write( " |