document.write( "Question 896065: A rectangle is twice as long as it is wide. The perimeter is 60 feet. Find the dimensions. \n" ); document.write( "
Algebra.Com's Answer #543204 by JulietG(1812)\"\" \"About 
You can put this solution on YOUR website!
P = 2L + 2W
\n" ); document.write( "P = 60
\n" ); document.write( "L = 2W
\n" ); document.write( "Insert the known values.
\n" ); document.write( "P = 2L + 2W
\n" ); document.write( "60 = 2(2W) + 2W
\n" ); document.write( "Distribute
\n" ); document.write( "60 = 4W + 2W
\n" ); document.write( "60 = 6W
\n" ); document.write( "Divide each side by 6
\n" ); document.write( "W = 10
\n" ); document.write( "If the width is 10 and the length is twice that, it's 20.
\n" ); document.write( "20+20+10+10 = 60
\n" ); document.write( "
\n" );