document.write( "Question 895971: log 25 + log 64 \n" ); document.write( "
Algebra.Com's Answer #543124 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! Assuming we're dealing with log base 10\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "log(25) + log(64) = log(25*64)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "log(25) + log(64) = log(1600)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "log(25) + log(64) = log(16*100)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "log(25) + log(64) = log(16)+log(100)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "log(25) + log(64) = log(16)+2\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If you want to use a calculator, then log(25) + log(64) = 3.20411998265592 approximately \n" ); document.write( " \n" ); document.write( " |