document.write( "Question 895586: I need help putting this equation into standard form, and if it is a parabola I have to identify the vertex and focus. If its and ellipse or hyperbola I have to identify the vertices and foci. \r
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document.write( "X^2+12x+y+41=0 \r
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document.write( "I have gotten to (x-6)^2= (y+5) I need help completing the rest of it and identifying all of the things above please. \n" );
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Algebra.Com's Answer #543106 by Fombitz(32388)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Parabola with vertex (-6,-5) opens downwards. \n" ); document.write( "Focus \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Focus : (-6,-5-1/4)=(-6,-21/4) \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |