document.write( "Question 895586: I need help putting this equation into standard form, and if it is a parabola I have to identify the vertex and focus. If its and ellipse or hyperbola I have to identify the vertices and foci. \r
\n" ); document.write( "\n" ); document.write( "X^2+12x+y+41=0 \r
\n" ); document.write( "\n" ); document.write( "I have gotten to (x-6)^2= (y+5) I need help completing the rest of it and identifying all of the things above please.
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Algebra.Com's Answer #543106 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
\"x%5E2%2B12x%2By%2B41=0\"
\n" ); document.write( "\"x%5E2%2B12x%2B36%2By%2B41=36\"
\n" ); document.write( "\"%28x%2B6%29%5E2%2By%2B41=36\"
\n" ); document.write( "\"y=-%28x%2B6%29%5E2-5\"
\n" ); document.write( "Parabola with vertex (-6,-5) opens downwards.
\n" ); document.write( "Focus
\n" ); document.write( "\"y%2B5=-%28x%2B6%29%5E2\"
\n" ); document.write( "\"-%28y%2B5%29=%28x%2B6%29%5E2\"
\n" ); document.write( "\"4p=-1\"
\n" ); document.write( "\"p=-1%2F4\"
\n" ); document.write( "Focus : (-6,-5-1/4)=(-6,-21/4)
\n" ); document.write( "\"graph%28300%2C300%2C-10%2C2%2C-10%2C2%2C-%28x%2B6%29%5E2-5%29\"\r
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