document.write( "Question 895892: Please help me:
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\n" ); document.write( "a2=b2
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Algebra.Com's Answer #543099 by Edwin McCravy(20060)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "This the famous bogus proof that 2=1.  \r\n" );
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document.write( "1.  \"a\"\"%22%22=%22%22\"\"b\"                We can have two variables equal to each other.\r\n" );
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document.write( "2.  \"a%5E2\"\"%22%22=%22%22\"\"ab\"              We multiply both sides by a.\r\n" );
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document.write( "3.  \"a%5E2-b%5E2\"\"%22%22=%22%22\"\"ab-b%5E2\"       We subtract \"b%5E2\" from both sides\r\n" );
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document.write( "4.  \"%28a-b%29%28a%2Bb%29\"\"%22%22=%22%22\"\"b%28a-b%29\"   We factor both sides. \r\n" );
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document.write( "5.  \"a%2Bb\"\"%22%22=%22%22\"\"b\"              We divide both sides by (a-b)\r\n" );
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document.write( "6.  \"b%2Bb\"\"%22%22=%22%22\"\"b\"              We substitute b for a since a=b\r\n" );
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document.write( "7.  \"2b\"\"%22%22=%22%22\"\"b\"               We combine like terms on the left\r\n" );
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document.write( "8.  \"2\"\"%22%22=%22%22\"\"1\"                We divide both sides by b\r\n" );
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document.write( "It looks as though we have proved this proves that 2 equals 1.  But there is a\r\n" );
document.write( "flaw. The flaw is in step 5.  The rule for dividing both sides of an equation\r\n" );
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document.write( "\"Both sides of an equation can be divided by the same non-zero number.\"\r\n" );
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document.write( "However (a-b) is zero in disguise because a = b.  So step 5 is an error.\r\n" );
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document.write( "Edwin
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