document.write( "Question 895821: Six years hence a man?s age will be three times his son!s age and three years ago he was nine times as old as his son . Find their present ages? \n" ); document.write( "

Algebra.Com's Answer #543068 by JulietG(1812) $\"\"$ $\"About$

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M+6=3(S+6)
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\n" ); document.write( "M+6=3S+18
\n" ); document.write( "Subtract 6 from each side
\n" ); document.write( "M = 3S+12
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\n" ); document.write( "M-3 = 9(S-3)
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\n" ); document.write( "M-3=9s-27
\n" ); document.write( "Add 3 to each side
\n" ); document.write( "M = 9S-24
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\n" ); document.write( "Take the value of M from the first equation and substitute it for M in the second.
\n" ); document.write( "M = 9S-24
\n" ); document.write( "(3S+12)=9S-24
\n" ); document.write( "Subtract 3S from each side
\n" ); document.write( "12 = 6S-24
\n" ); document.write( "Add 24 to each side
\n" ); document.write( "36 = 6S
\n" ); document.write( "Divide each side by 6
\n" ); document.write( "S = 6
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\n" ); document.write( "If the son is 6 years old, then 3 years ago he was 3 years old. At that time, his dad was 9x his age, or 27. That was 3 years ago. Now he's 30.
\n" ); document.write( "Son=6
\n" ); document.write( "Dad=30\r
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