document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=895854>Question 895854</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangular hotel room is 72 feet. The room is 14 feet wide. How long is it? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #543065 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=543065\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Think of a perimeter as a fence.  It requires 2 lengths and 2 widths to enclose.<BR>\n" );
document.write( "P = 2L + 2W<BR>\n" );
document.write( "You're given the value of P as 72<BR>\n" );
document.write( "72 = 2L + 2W<BR>\n" );
document.write( "You're given the value of W<BR>\n" );
document.write( "72 = 2L + 2(14)<BR>\n" );
document.write( "72 = 2L + 28<BR>\n" );
document.write( "Subtract 28 from each side<BR>\n" );
document.write( "44 = 2L<BR>\n" );
document.write( "Divide each side by 2<BR>\n" );
document.write( "L = 22<BR>\n" );
document.write( "<br><BR>\n" );
document.write( "W = 14<BR>\n" );
document.write( "L = 22<BR>\n" );
document.write( "22 + 22 + 14 + 14 = 72 </SPAN>\n" );
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