document.write( "Question 895777: A hybrid car uses 50 miles per gallon of gas while driving in the city and 40 miles per gallon on the highway. The car has a 15 gallon gallon tank.\r
\n" );
document.write( "\n" );
document.write( "a. write an equation using C for city and H for highway to represent the cars gallons of gas used in the city and the highway: im completely confused.\r
\n" );
document.write( "\n" );
document.write( "b. write an expression to represent the miles the hybrid car can achieve: i think it is 40H + 50(15-H) i dont think so though\r
\n" );
document.write( "\n" );
document.write( "c.using parts 1 & 2, write a combined simplified expression to represent the above situation: completely lost again\r
\n" );
document.write( "\n" );
document.write( "d. what is the minimum and maximum distances the car can go?
\n" );
document.write( "minimum: idk maximum: i think its 600 miles
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #543025 by Theo(13342)![]() ![]() You can put this solution on YOUR website! H is the number of gallons the car will use when traveling on the highway. \n" ); document.write( "C is the number of gallons the car will use when traveling in the city.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "on one tank of gas, the car can use 15 gallons of gas.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this means that H + C = 15\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "from this equation, you can solve for H in terms of C to get H = 15 - C or you can also solve for C in terms of H to get C = 15 - H.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "either one of these equation will be helpful later.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "let's answer your questions part by part.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "a. write an equation using C for city and H for highway to represent the cars gallons of gas used in the city and the highway:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "number of miles the car can drive in the city = 50*C\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "number of miles the car can drive on the highway = 40*H\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-----\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "b. write an expression to represent the miles the hybrid car can achieve on a tankful of gas:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "number of miles the car can achieve is equal to:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "50*C + 40*H, where H + C is equal to 15.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-----\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "c.using parts 1 & 2, write a combined simplified expression to represent the above situation:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "i'm really not sure what they're driving at here either.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "i believe you already accomplished this with part b.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you can solve for H in terms of C and you will get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "H = 15 - C.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "replace h in the equation with 15 - C and you will get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "50*C + 40*(15-C)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the implicit assumption here is that H + C = 15 which was already stated above.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your equation of 50*(15-H) + 40*H would yield the same result.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you just solved for C in terms of H where I solved for H in terms of C.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "50*C + 40*(15 - C) is equivalent to 50*(15 - H) + 40*H.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "both would yield the same result.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "if C = 10, then 50*C + 40*(15 - C) = 50*10 + 40*5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "if H = 5, then 50*(15 - H) + 40*H = 50*10 + 40*5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "same result.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-----\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "d. what is the minimum and maximum distances the car can go?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "since the car achieves the greater number of miles when you are traveling in the city, then the maximum number of mile you can achieve is when C = 15 and H = 0 and the formula becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "50*15 + 40*0 = 750 miles.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "since the car achieves the least number of miles when you are traveling on the highway, then the minimum number of miles you can achieve is when C = 0 and H = 15 and the formula becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "50*0 + 40*15 = 600 miles.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-----\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |