document.write( "Question 895789: \"find two consecutive positive integers such that the square of the first is decreased by 17 equals 4 time the second.\" \n" ); document.write( "
Algebra.Com's Answer #543021 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
x is the first number.
\n" ); document.write( "x+1 is the second number.\r
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\n" ); document.write( "\n" ); document.write( "your equation becomes:\r
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\n" ); document.write( "\n" ); document.write( "x^2 - 17 = 4*(x+1)\r
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\n" ); document.write( "\n" ); document.write( "simplify this equation to get:\r
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\n" ); document.write( "\n" ); document.write( "x^2 - 17 = 4x + 4\r
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\n" ); document.write( "\n" ); document.write( "subtract 4x and subtract 4 from both sides of this equation to get:\r
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\n" ); document.write( "\n" ); document.write( "x^2 - 17 - 4x - 4 = 0\r
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\n" ); document.write( "\n" ); document.write( "simplify to get:\r
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\n" ); document.write( "\n" ); document.write( "x^2 - 4x - 21 = 0\r
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\n" ); document.write( "\n" ); document.write( "factor to get:\r
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\n" ); document.write( "\n" ); document.write( "(x-7) * (x+3) = 0\r
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\n" ); document.write( "\n" ); document.write( "solve for x to get:\r
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\n" ); document.write( "\n" ); document.write( "x = 7 or x = -3\r
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\n" ); document.write( "\n" ); document.write( "x has to be a positive integer so your solution appears to be 7.\r
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\n" ); document.write( "\n" ); document.write( "first number is 7
\n" ); document.write( "second number is 8\r
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\n" ); document.write( "\n" ); document.write( "7^2 - 17 = 49 - 17 = 32
\n" ); document.write( "4*8 = 32
\n" ); document.write( "first number squared minus 17 is equal to 4 times the second number so your solution is good.\r
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\n" ); document.write( "\n" ); document.write( "solution is x = 7.\r
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