document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=895659>Question 895659</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 8 more than twice the width. If the perimeter of the rectangle is 66 cm. , what are the measurements and area of the rectangle?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #542974 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=542974\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> w for width and L for length;\r<BR>\n" );
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document.write( "L=8+2w and 2w+2L=66; and the perimeter equation can be simplified before using, since is divisible by 2.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=w%2BL=33 ALIGN=MIDDLE  ALT=\"w%2BL=33\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "and just substitute for L.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=w%2B%288%2B2w%29=33 ALIGN=MIDDLE  ALT=\"w%2B%288%2B2w%29=33\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "and you know what to do now.....\r<BR>\n" );
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