document.write( "Question 895598: solve the equation for the indicated variable. a^2x+(a-5)=(a+5)x; for x
\n" ); document.write( "I tried everything from distributing to just leaving the parenthesis and doing order of operations. I always find that the x cancels out, which, of course, does not make any sense.
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Algebra.Com's Answer #542921 by lwsshak3(11628)\"\" \"About 
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solve the equation for the indicated variable.
\n" ); document.write( "a^2x+(a-5)=(a+5)x; for x
\n" ); document.write( "a^2x+a-5=ax+5x
\n" ); document.write( "a^2x-ax-5x=-a+5
\n" ); document.write( "x(a^2-a-5)=5-a
\n" ); document.write( "x=(5-a)/(a^2-a-5)
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