document.write( "Question 895508: A man travel 20 km at 40 km/h ,10km at 30 km pH and 30 km at 60 km pH determine the average speed? \n" ); document.write( "
Algebra.Com's Answer #542911 by ankor@dixie-net.com(22740)\"\" \"About 
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A man travels 20 km at 40 km/h, 10km at 30 km pH, and 30 km at 60 km pH
\n" ); document.write( " determine the average speed?
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\n" ); document.write( "Total distance = 20 + 10 + 30 = 60 km
\n" ); document.write( "Let a = the average speed of the whole trip
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\n" ); document.write( "Write a time equation; time = dist/speed
\n" ); document.write( "\"20%2F40\" + \"10%2F30\" + \"30%2F60\" = \"60%2Fa\"
\n" ); document.write( "multiply equation by 120a, cancel the denominators and you have
\n" ); document.write( "(3a(20) + 4a(10) + 2a(30) = 120(60)
\n" ); document.write( "60a + 40a + 60a = 7200
\n" ); document.write( "160a = 7200
\n" ); document.write( "a = 7200/160
\n" ); document.write( "a = 45 km/hr is the average speed
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\n" ); document.write( "Check this by finding the time
\n" ); document.write( "\"20%2F40\" + \"10%2F30\" + \"30%2F60\" = \"60%2F45\"
\n" ); document.write( ".5 + .33 + .5 = 1.33
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