document.write( "Question 75623This question is from textbook Elementary algebra
\n" ); document.write( ": Solve F = 9C+160/5 for C\r
\n" ); document.write( "\n" ); document.write( "I know how do this going the other way, but I can't figure it out this way.
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Algebra.Com's Answer #54291 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"F+=+%289C%2B160%29%2F5\"
\n" ); document.write( "\"F+=+%289%2F5%29C%2B32\" reduce 160/5 to 32
\n" ); document.write( "\"F+-+32+=+%289%2F5%29C%2Bcross%2832-32%29\" Subtract 32 from both sides
\n" ); document.write( "\"%285%2F9%29%28F+-+32%29+=+cross%28%285%2F9%29%289%2F5%29%29C\" Multiply both sides by 5/9. This cancels the 9/5 on the right side
\n" ); document.write( "\"C=%285%2F9%29%28F+-+32%29\" So this is what C equals
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