document.write( "Question 895481: A balloon rising vertically with a velocity of 16 ft/sec, releases a sandbag at an instant when the ballon is 64 ft. above the ground. Compute the position of the sandbag 1/4 sec. after its release. \n" ); document.write( "
Algebra.Com's Answer #542888 by Edwin McCravy(20060)\"\" \"About 
You can put this solution on YOUR website!
The formula is\r\n" );
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document.write( "\"h=h%5B0%5D%2Bv%5B0%5Dt-16t%5E2\"\r\n" );
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document.write( "h = final height in feet\r\n" );
document.write( "h0 = the initial height in feet\r\n" );
document.write( "v0 = the initial velocity in ft/sec\r\n" );
document.write( "t = the final time.\r\n" );
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document.write( "h = what we are looking for.\r\n" );
document.write( "h0 = 64 ft\r\n" );
document.write( "v0 = 16 ft/sec\r\n" );
document.write( "t = 1/4 sec\r\n" );
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document.write( "\"h=h%5B0%5D%2Bv%5B0%5Dt-16t%5E2\"\r\n" );
document.write( "\"h=64%2B16%281%2F4%29-16%281%2F4%29%5E2\"\r\n" );
document.write( "\"h=64%2B4-16%281%2F16%29\"\r\n" );
document.write( "\"h=68-1\"\r\n" );
document.write( "\"h=67\"\r\n" );
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document.write( "Answer: 67 feet above the ground\r\n" );
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document.write( "[Notice: Since the balloon was going up when the\r\n" );
document.write( "sandbag was released, the sandbag was still going up\r\n" );
document.write( "1/4 of a second after it was released.  It had not\r\n" );
document.write( "started to fall yet.] \r\n" );
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document.write( "Edwin

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