document.write( "Question 895466: A woman is 3 times as old as her son . 8 years ago the product of their child was 112. Find thier present age.
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Algebra.Com's Answer #542826 by stanbon(75887) $\"\"$ $\"About$

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A woman is 3 times as old as her son . 8 years ago the product of their ages was 112. Find thier present age.
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\n" ); document.write( "Equations:
\n" ); document.write( "w = 3s
\n" ); document.write( "(w-8)(s-8) = 112
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\n" ); document.write( "Substitute for \"w\" and solve for \"s\"::
\n" ); document.write( "(3s-8)(s-8) = 112
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\n" ); document.write( "3s^2 - 24s - 8s + 64 = 112
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\n" ); document.write( "3s^2 - 32s - 48 = 0
\n" ); document.write( "Factor::
\n" ); document.write( "(s-12)(3s+4) = 0
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\n" ); document.write( "Positive solution::
\n" ); document.write( "s = 12 yrs (the son's age now)
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\n" ); document.write( "Solve for \"w\"::
\n" ); document.write( "w = 3s
\n" ); document.write( "w = 36 yrs (the woman's age now)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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