document.write( "Question 895138:  A lot is in the shape of a rectangle with a perimeter of 66 meters.  The length is 4 meters less than twice the width. Find the length. 
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document.write( "I need help setting this up please. I have attempted to set up the equation below but when I plug in the numbers I am missing something.  Thank you.\r
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document.write( "Length= 4 meters - 2x (x)
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document.write( "width= x
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document.write( "perimeter = 66 meters \n" );
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| Algebra.Com's Answer #542808 by lwsshak3(11628)      You can put this solution on YOUR website! A lot is in the shape of a rectangle with a perimeter of 66 meters. The length is 4 meters less than twice the width. Find the length. \n" ); document.write( "*** \n" ); document.write( "let x=width \n" ); document.write( "2x-4=length \n" ); document.write( "2(length+width)=perimeter \n" ); document.write( "2(2x-4+x)=66 \n" ); document.write( "6x-8=66 \n" ); document.write( "6x=74 \n" ); document.write( "x=74/6=37/3 \n" ); document.write( "2x-4=(2*37/3)-4=74/3-4=74/3-12/3=62/3 \n" ); document.write( "length=62/3 meters \n" ); document.write( " |