document.write( "Question 895303: Five years ago, a mother was twice as old as her son. In 6years time,the sum of their ages will be 82. Find their present ages \n" ); document.write( "

Algebra.Com's Answer #542753 by mark_henrhiz(40) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"x-5+=+2%28y-5%29\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"x%2B6+%2B+y%2B6+=+82\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"x-5+=+2y-10\"$
\n" ); document.write( " $\"x-2y+=+-10%2B5\"$
\n" ); document.write( " $\"x-2y+=+-5\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"x%2By+=+82-12\"$
\n" ); document.write( " $\"x%2By+=+70\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"x-2y+=+-5\"$
\n" ); document.write( " $\"x%2By+=+70\"$ then you solve it either through substitution method or
\n" ); document.write( "addition method \n" ); document.write( "

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