document.write( "Question 895319: The equation y=-2x^2-12x-10 to y-k=a(x-h)^2 form \n" ); document.write( "
Algebra.Com's Answer #542741 by Edwin McCravy(20060)![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( " y = -2x² - 12x - 10\r\n" ); document.write( "\r\n" ); document.write( "Factor -2 out of only the first two terms on the right\r\n" ); document.write( "\r\n" ); document.write( " y = -2(x² + 6x) - 10\r\n" ); document.write( "\r\n" ); document.write( "Complete the square inside the parentheses:\r\n" ); document.write( "1. Multiply the coefficient of x, which is +6 times 1/2, getting +3\r\n" ); document.write( "2. Square +3 getting +9\r\n" ); document.write( "3. Add and subtract 9 inside the parentheses \r\n" ); document.write( "\r\n" ); document.write( " y = -2(x² + 6x + 9 - 9) - 10\r\n" ); document.write( "\r\n" ); document.write( "Change the parentheses to brackets and group the first \r\n" ); document.write( "three terms inside the bracket in parentheses:\r\n" ); document.write( "\r\n" ); document.write( " y = -2[(x² + 6x + 9) - 9] - 10\r\n" ); document.write( "\r\n" ); document.write( "Factor the trinomial inside the parentheses as a perfect square\r\n" ); document.write( "That is, go straight to it or else x²+6x+9 = (x+3)(x+3) = (x+3)²\r\n" ); document.write( "\r\n" ); document.write( " y = -2[(x + 3)² - 9] - 10\r\n" ); document.write( "\r\n" ); document.write( "Remove the bracket by distributing, leaving the (x+3)² intact:\r\n" ); document.write( "\r\n" ); document.write( " y = -2(x + 3)² + 18 - 10\r\n" ); document.write( "\r\n" ); document.write( "Combine the constant terms on the right\r\n" ); document.write( "\r\n" ); document.write( " y = -2(x + 3)² + 8\r\n" ); document.write( "\r\n" ); document.write( "Add -8 to both sides:\r\n" ); document.write( "\r\n" ); document.write( "y - 8 = -2(x + 3)²\r\n" ); document.write( "\r\n" ); document.write( "Edwin\n" ); document.write( " |