document.write( "Question 895200: hi i was wondering how i am supposed to graph the following function: f(x)=-1/3(x)+2 on domain [-2,8]. thank you. \n" ); document.write( "
Algebra.Com's Answer #542713 by jim_thompson5910(35256)\"\" \"About 
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Graph the line y = (-1/3)x + 2 on the xy axis like so\r
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\n" ); document.write( "\n" ); document.write( "This line goes through (0,2) and (3,1). To get any point on this line, plug in a specific x value (like x = 0) into y = (-1/3)x + 2 and compute it to get the corresponding y value.\r
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\n" ); document.write( "\n" ); document.write( "That's the entire graph shown above. We just want it graphed on the domain [-2,8]. So what we do is erase the portion to the left of -2 and to the right of 8\r
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\n" ); document.write( "\n" ); document.write( "Basically we only graph if x is between -2 and 8 (inclusive to both endpoints)\r
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\n" ); document.write( "\n" ); document.write( "Doing so gives us this final answer\r
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\n" ); document.write( "\n" ); document.write( "Notice how the red endpoints are at x = -2 and x = 8. These endpoints are closed circles to signify that we are including the endpoints.
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