document.write( "Question 895284: Sally has $70,000 to invest. She invests some money at 7% interest and the rest at 11%. If her total annual income from these two investments is $7,100, how much does she invest at each rate? \n" ); document.write( "
Algebra.Com's Answer #542691 by reviewermath(1029)![]() ![]() You can put this solution on YOUR website! Q: \n" ); document.write( "Sally has $70,000 to invest. She invests some money at 7% interest and the rest at 11%. If her total annual income from these two investments is $7,100, how much does she invest at each rate? \n" ); document.write( "A: \n" ); document.write( "Let x = amount invested at 7% interest \n" ); document.write( "therefore, 70000 - x = amount invested at 11% interest \n" ); document.write( "0.07x + 0.11(70000 - x) = 7100 \n" ); document.write( "Multiply both sides by 100 \n" ); document.write( "7x + 11(70000 - x) = 710000 \n" ); document.write( "7x + 770000 - 11x = 710000 \n" ); document.write( "-4x = -60000 \n" ); document.write( "x = 15000 \n" ); document.write( "so 70000 - x = 55000 \n" ); document.write( "Amount invested at 7% = 15000 dollars \n" ); document.write( "Amount invested at 11% = 55000 dollars \n" ); document.write( " \n" ); document.write( " |