document.write( "Question 895160: 3 ladies and 3 gents can be seated at a round table sothat any two and only two of ladies sit together number of ways is? \n" ); document.write( "
Algebra.Com's Answer #542671 by Edwin McCravy(20055)![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "When the problem says \"round table\", that means it's as if the table\r\n" ); document.write( "and people were on a turntable floor. So there are only these two\r\n" ); document.write( "seating schemes where exactly 2 women sit together.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " W W W W\r\n" ); document.write( " \r\n" ); document.write( " M M M M\r\n" ); document.write( " \r\n" ); document.write( " M W W M\r\n" ); document.write( "\r\n" ); document.write( "For each of these two arrangments there are 3! ways to place the women\r\n" ); document.write( "and 3! ways to place the men. Thats 3!*3! = 6*6 = 36 ways for each.\r\n" ); document.write( "Since there are 2 seating schemes above, we double that number. \r\n" ); document.write( "\r\n" ); document.write( "Answer = 2*36 = 72\r\n" ); document.write( "\r\n" ); document.write( "Edwin \n" ); document.write( " \n" ); document.write( " |