document.write( "Question 895247: Jasmine drew a rectangle with the following properties.
\n" ); document.write( "The area is 45 square centimeters.\r
\n" ); document.write( "\n" ); document.write( "The length is 5 times the width
\n" ); document.write( " what is the perimiter
\n" ); document.write( "

Algebra.Com's Answer #542667 by MathTherapy(10552)\"\" \"About 
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Jasmine drew a rectangle with the following properties.
\n" ); document.write( "The area is 45 square centimeters.\r
\n" ); document.write( "\n" ); document.write( "The length is 5 times the width
\n" ); document.write( " what is the perimiter
\n" ); document.write( "

\n" ); document.write( "Let width be W
\n" ); document.write( "Then length = 5W
\n" ); document.write( "Since area = 45 sq cm, then: W(5W) = 45
\n" ); document.write( "\"5W%5E2+=+45\"
\n" ); document.write( "\"W%5E2+=+45%2F5\"
\n" ); document.write( "Width, or \"W+=+sqrt%2845%2F5%29\", or W = 3
\n" ); document.write( "Therefore, length = 5(3), or 15 cm
\n" ); document.write( "Perimeter: 2W + 2L, or 2(3) + 2(15), or 6 + 30, or \"highlight_green%2836%29\" cm \n" ); document.write( "
\n" );