document.write( "Question 895247: Jasmine drew a rectangle with the following properties.
\n" ); document.write( "The area is 45 square centimeters.\r
\n" ); document.write( "\n" ); document.write( "The length is 5 times the width
\n" ); document.write( " what is the perimiter
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Algebra.Com's Answer #542663 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
You know this:
\n" ); document.write( "If w is width, and L is length,\r
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\n" ); document.write( "\n" ); document.write( "wL=A, using A for area.
\n" ); document.write( "Given: L=5w
\n" ); document.write( "p=2w+2L, using p for perimeter.\r
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\n" ); document.write( "\n" ); document.write( "Can you find w, and L, using these facts as symbolized?\r
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\n" ); document.write( "\n" ); document.write( "\"wL=A\"
\n" ); document.write( "\"w%2A5w=A\"
\n" ); document.write( "\"5w%5E2=A\"
\n" ); document.write( "\"w=sqrt%28A%2F5%29\"
\n" ); document.write( "-
\n" ); document.write( "\"L=5w\"
\n" ); document.write( "\"L=5%2Asqrt%28A%2F5%29\"
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\n" ); document.write( "The question asks for p, or perimeter.
\n" ); document.write( "\"p=2w%2B2L\"
\n" ); document.write( "\"highlight_green%28p=2%2Asqrt%28A%2F5%29%2B2%2A5%2Asqrt%28A%2F5%29%29\"
\n" ); document.write( "You can adjust this as \"%282%2B2%2A5%29sqrt%28A%2F5%29\"
\n" ); document.write( "\"p=12%2Asqrt%28A%2F5%29\"----which should be easier.\r
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\n" ); document.write( "\n" ); document.write( "Finish using the given value for A=45, and evaluate p.
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